Slide 1: Let’s take a look to see how we can use the Hardy-Weinberg Equation to help us find out the exact genotypes in our founder’s population. P2 + 2pq + q2 = 1 p = dominant alleles Slide 2: To solve the equation we must know the variables. In this equation p = the dominant alleles (homozygous dominant) and q = the recessive alleles (homozygous recessive). The combination of pq found in our population is going to be the heterozygous individuals. P2 + 2pq + q2 = 1 p = dominant alleles (or the homozygous dominant genotype) q = recessive alleles (or the homozygous recessive genotype) pq = a combination of both (or the heterozygous genotype) Slide 3: We know that the alleles make up 100% of the population, there is no individual in the population without two alleles. We know that our alleles for color are listed as capitol B dominant and lowercase b recessive so we can take this step. P2 + 2pq + q2 = 1 p = dominant alleles, ladybugs B q = recessive alleles, ladybugs b Slide 4: We can fill in what we know. All that we were given by the Galapagos scientists was that 20% of the alleles were dominant. From this we can figure 100% of the alleles -20% dominant alleles = 80% This means that 80% of the alleles were recessive. P2 + 2pq + q2 = 1 p =.2 q = .8 Now we can take this step: (.2)2 + 2 (.20 x .8) + (.8)2 = 1 Slide 5: Now we just need to do the math. Remember, we are looking at 100% of the population. So to get percentages, we will need to multiply each by a hundred before we make our comparison. P2 + 2pq + q2 = 1 .04 + 2(.16) + .64 =1 .04 + .32 + .64 =1 Slide 6: Now we have the breakdown of genotypes from the founders population. We just need to add the phenotype and compare this population to the one we saw today. Let’s go back to the galley and look at our notes. I can’t wait to see how they compare. BB was dominant(homozygous dominant) = 4% of the population bb was recessive(homozygous recessive) = 64 % of the population Bb inherited both (heterozygous) = 32% of the population |